判别级数
∑[1/(2n+1)+1/(2n+2)]
的敛散性用不着柯西收敛准则,用比较判别法足矣:因
lim(n→∞)[1/(2n+1)+1/(2n+2)]/(1/n)
= lim(n→∞)[1/(2+1/n)+1/(2+2/n)]
= 1/2+1/2 = 1,
而级数 ∑(1/n) 发散,据比较判别法知原级数发散.
判别级数
∑[1/(2n+1)+1/(2n+2)]
的敛散性用不着柯西收敛准则,用比较判别法足矣:因
lim(n→∞)[1/(2n+1)+1/(2n+2)]/(1/n)
= lim(n→∞)[1/(2+1/n)+1/(2+2/n)]
= 1/2+1/2 = 1,
而级数 ∑(1/n) 发散,据比较判别法知原级数发散.