Question

2的y次方+2的x次方=6,则2的x+y次方的最大值

Answer 1

2^y+2^x=6

6=2^y+2^x≥2√[2^(x+y)]

3≥√[2^(x+y)]

2^(x+y)]≤9

(2^(x+y)])(MAX)=9