递等式计算:[1-328÷(328×2.5)]÷2.4 1 1 4 ×17.6+36÷ 4 5 +26.4×12.5.2

1个回答

  • (1)[1-328÷(328×2.5)]÷2.4

    =[1-328÷328÷2.5]÷2.4,

    =[1-1÷2.5]÷2.4,

    =[1-0.4]÷2.4,

    =0.6÷2.4,

    =0.25;

    (2) 1

    1

    4 ×17.6+36÷

    4

    5 +26.4×1.25

    =1.25×17.6+36×1.25+26.4×1.25,

    =(17.6+26.4+36)×1.25,

    =80×1.25,

    =100;

    (3)201.2×

    22

    25 +2012×

    3

    200 -20.12×

    3

    10

    =2012×

    22

    25 ×

    1

    10 +2012×

    3

    200 -2012×

    3

    10 ×

    1

    100 ,

    =(

    22

    250 +

    3

    200 -

    3

    1000 )×2012,

    =(

    88

    1000 +

    15

    1000 -

    3

    1000 )×2012,

    =

    1

    10 ×2012,

    =201.2;

    (4)[47-(18.75-1÷

    8

    15 )×2]÷0.46

    =[47-(18.75-1.875)×2]÷0.46,

    =[47-16.875×2]÷0.46,

    =[47-33.75]÷0.46,

    =13.25÷0.46,

    =

    1325

    46 .