Question

若x^2-3x+1=0,则(x^3+x^2+x)/(x^4+x^2+1)的值为

Answer 1

(X^3+X^2+x)/(x^4+x^2+1)=[X(x^2+X+1)]/[(x^2+X+1)(x^2-X+1)]=X/(x^2-X+1)=X/(x^2-3X+1+2X)=X/(0+2X)=X/2X=1/2