1 .求式 =x^2+y^2+2xy=9-4-4=1
2 求式 =x^2+y^2-2xy=9+4+4=17
已知x^2+y^2=9,xy=-4,求(1)(x+y)^2;(2)(x-y)^2
1个回答
相关问题
-
已知X+Y=3,XY=-1,求2(X-Y)^4-9(X-Y)^2+12XY
-
已知1/x-1/y=4,求(2x+xy-2y)/(x-2xy-y)
-
已知x^2-xy=4,y^2-xy=9,求代数式x^2-2xy+y^2
-
已知x2+4y2+x2y2-6xy+1=0,求 x4-y4/2x-y 乘 2xy-y2/xy-y2 除以（x2+y2/x
-
已知x2+4y2+x2y2-6xy+1=0,求 x4-y4/2x-y 乘 2xy-y2/xy-y2 除以（x2+y2/x
-
已知x+2y=5,xy=1求2x^2y+4xy^2求1-二分之一x^2y-xy^2求(x^2+1)(4y^2+1)
-
已知2x-y=1,xy=2,求(xy-5x-2y)-(-3xy-x-4y)=
-
已知x+y=2,xy=1/2,求x³y+2x²y²+xy³
-
已知(4x-y-1)^2+根号x+y-2=0,求4x^2y-4xy+xy^2
-
.已知:x-y=1,xy=-2.求:(-2xy+2 x+3y)-(3xy+2y-2x)-(x+4y+xy)的值