Question

已知a=9,b=-1/9,求a^(2n+2)*b^2n*b^4的值

Answer 1

ab=9*(-1/9)=-1

a^(2n+2)*b^2n*b^4

=a^(2n+2)*b^(2n+2)*b^2

=(ab)^(2n+2)*b^2

=(-1)^(2n+2)*(-1/9)^2

=1*(1/81)

=1/81