要选择题的话可以随便代个符合条件的数进去;
证明题的:∵a>b>0 ∴b/a<1<a/b
b+m/a+m-b/a=(a-b)m/(a+m)a ∵(a-b)m>0,(a+m)a,∴b+m/a+m>b/a
a+n/b+n-b+m/a+m=((a+b+m+n)(a-b)/(a+m)(b+n) ∵a-b>0,a>b>0,m>0,n>0,∴a+n/b+n>b+m/a+m
a/b-a+n/b+n=n(a-b)/b(b+n) ∵ a-b>0,a>b>0,n>0,∴a/b>a+n/b+n
综上所述,a/b>a+n/b+n>b+m/a+m>b/a