Question

设ABC为正数,且满足A^+B^=C^,若log4(1+[B+C]\A)=1,log8(A+B-C)=2\3,ABC是个

Answer 1

log4(1+[B+C]A)=1=log4(4)

==>1+[B+C]/A=4

==>3A=B+C

log8(A+B-C)=23=log8(4)

==>A+B-C=4

==>B=A+2,C=2(A-1)

A^2+B^2=C^2

==>2A^2-12A=0

==>A=6

==>A=6,B=8,C=10