1.
(x-3)(x+1)>0
x3
2.
cos2α=2cos²α-1=2*3/5*3/5-1=-7/25
sin(2α-π/6)=sin2αcosπ/6-cos2αsinπ/6
=24/25*√3/2-7/25*1/2
=-7√3/50+12/25
=(24-7√3)/50
3.
|x-1|
1.
(x-3)(x+1)>0
x3
2.
cos2α=2cos²α-1=2*3/5*3/5-1=-7/25
sin(2α-π/6)=sin2αcosπ/6-cos2αsinπ/6
=24/25*√3/2-7/25*1/2
=-7√3/50+12/25
=(24-7√3)/50
3.
|x-1|