解
(2x-√2)²=0
∴2x-√2=0
∴x=√2/2
(2x-1)²=9
2x-1=3或2x-1=-3
2x=4或2x=-2
x=2或x=-1
(x+3)²=(1-2x)²
x+3=1-2x或x+3=-(1-2x)
3x=-2或-x=-4
∴x=-2/3或x=4
3(1-2x)²=48
(1-2x)²=16
1-2x=4或1-2x=-4
-2x=3或-2x=-5
x=-3/2或x=5/2
解
(2x-√2)²=0
∴2x-√2=0
∴x=√2/2
(2x-1)²=9
2x-1=3或2x-1=-3
2x=4或2x=-2
x=2或x=-1
(x+3)²=(1-2x)²
x+3=1-2x或x+3=-(1-2x)
3x=-2或-x=-4
∴x=-2/3或x=4
3(1-2x)²=48
(1-2x)²=16
1-2x=4或1-2x=-4
-2x=3或-2x=-5
x=-3/2或x=5/2