Question

二元一次方程,这个怎么解

Answer 1

9(2x-3)^2=16(x+4)^2

[3(2x-3)]^2=[4(x+4)]^2

(6x-9)^2=(4x+16)^2

则6x-9=4x+16

2x=25

x=25/2

或6x-9=-4x-16

10x=-7

x=-7/10