若m-n=2,a-n=3,则式子[(2m-2n-4)²;+(a-n-3)²]÷[(m+n+a)
1个回答
=[(4-4)(4-4)+(3-3)(3-3)]/ [(m+n+a)²+1]
=0/ [(m+n+a)²+1]
=0
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