Question

匀强电场场强E=100V/m,A、B点相距10cm,A、B连线与电场线夹角为60°,(1)求UAB

Answer 1

(1)UAB=E*Lcos60°=100*0.1*0.5=5v

(2)WAB=qUAB=1*10^-8*5=5*10^-8J