Question

一道初一分式题计算：根号6+4倍根号3+3倍根号2---------------------------(根号6+根号3

Answer 1

原式=(√6+√3+3√3+3√2)/(√6+√3)(√3+√2)

=(√6+√3)/(√6+√3)(√3+√2)+(3√3+3√2)/(√6+√3)(√3+√2)

=1/(√3+√2)+3/(√6+√3)

=(√3-√2)/(√3-√2)(√3+√2)+3(√6-√3)/(√6-√3)(√6+√3)

=(√3-√2)/(3-2)+3(√6-√3)/(6-3)

=√3-√2+√6-√3

=√6-√2