1.
相等,理由如下
∵BE CD是∠ABC和∠ACB的平分线
∴∠EBC=1/2∠ABC,∠DCB=1/2∠ACB
∵∠EBC=∠DCB
∴1/2∠ABC=1/2∠ACB即∠ABC=∠ACB
2.
∵在△ABC中,∠A=60
∴∠ABC+∠ACB=120
∵BE CD是∠ABC和∠ACB的平分线
∴∠EBC=1/2∠ABC,∠DCB=1/2∠ACB
∴∠EBC+∠DCB=1/2(∠ABC+∠ACB)=60
∵在△BOC中,∠EBC+∠DCB=60
∴∠BOC=120
1.
相等,理由如下
∵BE CD是∠ABC和∠ACB的平分线
∴∠EBC=1/2∠ABC,∠DCB=1/2∠ACB
∵∠EBC=∠DCB
∴1/2∠ABC=1/2∠ACB即∠ABC=∠ACB
2.
∵在△ABC中,∠A=60
∴∠ABC+∠ACB=120
∵BE CD是∠ABC和∠ACB的平分线
∴∠EBC=1/2∠ABC,∠DCB=1/2∠ACB
∴∠EBC+∠DCB=1/2(∠ABC+∠ACB)=60
∵在△BOC中,∠EBC+∠DCB=60
∴∠BOC=120