Question

计算:(1)4xy²÷(-2x的-2次方yz的-1次方);

Answer 1

(1)

4xy²÷(-2x^(-2)yz^(-1))

=-2xy²*x²z/y

=-2x³yz

(2)

[1-1/(a+1)]÷a/(a²+2a+1)

=a/(a+1)*(a²+2a+1)/a

=a+1

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