一道高一数学对数计算题,急【15题】

2个回答

原式= (lg2)^2 (1+2lg5) + (lg5)^2 (1+2lg2)
= (lg2 )^2 + (lg5)^2 + 2lg2 lg5(lg2 +lg5)
= (lg2 +lg5)^2 -2 +2lg2lg5
= 1-2 +2lg2lg5
= 2lg2lg5-1似乎不可再化简了