(x²+x+1)(x²-x+1) 计算 (3a+b-2)(3a-b+2)
2个回答
(x²+x+1)(x²-x+1)
=(x²+1)²-x²
=x^4+x²+1
(3a+b-2)(3a-b+2)
=9a²-(b-2)²
=9a²-b²+4b-4
相关问题
计算:-3x+(x-1)-(3x-3)= 2(a-2)-3(a+1)= -(5a-4b)+2(a-2b)=
计算:(1).(a+b)(a²-b²) (2).(2x-1)(4x²+2x+1) (3).
计算:(1)x+1/x-1/x,(2)a/b+1+2a/b+1-3a/b+1
化简(1+1/x-1)÷x/x^2-1=?计算(x^2/x-1)-x=?化简1-3a/2b÷3a/2b*2b/3a=?计
计算:①(a+b)(a-2b)-(a+2b)(a-b) ②5x(x2+2x+1)-(2x+3)(x-5)
计算:1.(2x+7)(3x-4)+(3x+5)(3-2x)2.[(a-3b)(a+3b)-(3b-a)²]÷
计算:(-2a/b^2)^2*(b^3/4a^ 计算:(x+3/x^2-3x-x-1/x^2-6x+9)/x-9/x的值
用平方公式计算:1、{a-2-3} {a-b-3}= 2、{x-2} {x+2} -{x+1} {x-3} = 3、{a
计算:(1)[a+9b/3ab−a+3b3ab](2)x2−1(x−1)2÷1x−1•1x+1.
1.计算:(1)(2a+3b) (2a-b) (2) 5x^2 (x+1)(x-1) (3) (2x+y-1)^22.计