Question

将y(y+1)(x^2+1)+x(2y^2+2y+1)因式分解

Answer 1

y(y+1)(x^2+1) + x(2y^2+2y+1) = y(y+1)(x^2+1) + x(2y^2+2y） + x = y(y+1)(x^2+1) + 2xy(y+1) + x = y(y+1)(x^2+2x+1) + x = y(y+1)(x+1)^2 + (x+1) - 1 =[(x+1) + (y+1)][(x+1) - y] =(x+y+2)(x-y+1)