根据弧长和弦长求半径怎么算?公式我没有看懂!

1个回答

  • Rn+1=(1+(L-2*Rn*SIN(C/(2*Rn)))/(L-C*COS(C/(2*Rn))))*Rn

    取R0,代入上式,得R1

    取R1,代入上式,得R2

    取R2,代入上式,得R3

    .

    直到Rn与Rn+1很接近即得R=Rn

    弧长900,弦长885;

    R0=1500

    R1=1407.095

    R2=1419.189

    R3=1419.453

    R3=1419.453

    R=1419.453

    弧长913,弦长900;

    R0=1500

    R1=1553.274

    R2=1558.423

    R3=1558.466

    R4=1558.466

    R=1558.466

    弧长930,弦长900;

    R0=1000

    R1=1045.885

    R2=1051.724

    R3=1051.806

    R4=1051.806

    R=1051.806

    弧长918,弦长900;

    R0=1000

    R1=1180.433

    R2=1296.279

    R3=1331.664

    R4=1334.237

    R5=1334.25

    R6=1334.25

    R=1334.25

    弧长932,弦长900;

    R0=1000

    R1=1020.292

    R2=1021.366

    R3=1021.369

    R4=1021.369

    R=1021.369