H2SO4+Ba(OH)2=BaSO4↓+2H2O
n(H2SO4)=n[Ba(OH)2]==0.025×0.020
c(H2SO4)=0.025mol/L
C点时混合溶液pH=7,说明正好中和
2n(H2SO4)+n(HCl)=2n[Ba(OH)2]
2×0.025×0.020+c(HCl)×0.020=2×0.025×0.060
c(HCl)=0.100mol/L
A点:n(H+)=0.100mol/L×0.020L=0.002mol
c(H+)=0.002/0.040=0.05mol/L
pH=-lg0.05=2-0.7=1.3
B点:n(H+)=0.001mol
c(H+)=0.001/0.060=(0.1/6)mol/L
pH=-lg(0.1/6)=1+2lg3=2