Question

代数式x-y/x/(x-2xy-y2/x)怎么算

Answer 1

原式=[(x-y)/x]/[(x²-2xy+y²)/x]

=[(x-y)/x]×[x/(x²-2xy+y²)]

=(x-y)/(x²-2xy+y²)

=(x-y)/(x-y)²

=1/(x-y)