（x+2y+2m)(2x-y+n)
=2x^2-xy+nx+4xy-2y^2+2ny+4mx-2my+2mn
=2x^2+3xy-2y^2+(4m+n)x-(2m-2n)y+2mn
=2x^2+3xy-2y^2+5y-2
所以4m+n=0且2m-2n=-5且2mn=-2
所以m=-1/2,n=2.
（x+2y+2m)(2x-y+n)=2x^2+3xy-2y^2+5y-2 求m、n的值!
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