﹙1﹚b²-4ac=4﹙m+1﹚²-4m²=8m+4≥0
m≥﹣1/2,且m≠0;
﹙2﹚x1+x2=﹣2﹙m+1﹚/m
x1·x2=1
x1²+x2²=﹙x1+x2﹚²-2x1x2=6
4[﹙m+1﹚/m]²-2=6
﹙m+1﹚/m=±√2
① ﹙m+1﹚/m=√2
m=√2+1
② ﹙m+1﹚/m=﹣√2
m=1-√2.
﹙1﹚b²-4ac=4﹙m+1﹚²-4m²=8m+4≥0
m≥﹣1/2,且m≠0;
﹙2﹚x1+x2=﹣2﹙m+1﹚/m
x1·x2=1
x1²+x2²=﹙x1+x2﹚²-2x1x2=6
4[﹙m+1﹚/m]²-2=6
﹙m+1﹚/m=±√2
① ﹙m+1﹚/m=√2
m=√2+1
② ﹙m+1﹚/m=﹣√2
m=1-√2.