Question

如图:在三角形ABC中,角ACB=90度,AC=BC,BE垂直CE,AD垂直CE于D 求证AD=BE+DE啊

Answer 1

因为,在△ACD和△CBE中,∠ADC = 90°= ∠CEB,∠CAD = 90°-∠ACD = ∠BCE ,AC = CB ,

所以,△ACD ≌ △CBE ,

可得：AD = CE ,CD = BE ,

所以,AD = CE = CD+DE = BE+DE .