Question

已知x的平方+y的平方+xy-3y+3等于0,求x的y次方是多少?

Answer 1

x^2+y^2+xy-3y+3=0

(x^2+xy+y^2/4)+(3y^2/4-3y+3)=0

(x+y/2)^2+3(y^2/4-y+1)=0

(x+y/2)^2+3(y/2-1)^2=0

∴x+y/2=0

y/2-1=0

∴y/2=1

y=2

x=-y/2=-1

∴x^y=(-1)^2=1