y=e^2x+x^2-yarcsin(1／x)
y'=2e^2x+2x-y'arcsin(1／x)+y1/[x^2*√(1-1/x^2)]
y'={2e^2x+2x+y1/[x^2*√(1-1/x^2)]}/[1+arcsin(1／x)]
dy={2e^2x+2x+y1/[x^2*√(1-1/x^2)]}/[1+arcsin(1／x)]dx
y=e^2x+x^2-yarcsin(1／x),求y′及dy
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