Question

1.（a-1)(a^2+a+1) 2.（m-1)(m+1)(m^2-1) 3.已知a-b=1/5,a^2+b^2=2又1

Answer 1

1.（a-1)(a^2+a+1) =a^3-12.（m-1)(m+1)(m^2-1)=(m^2-1)^2 3.已知a-b=1/5,a^2+b^2=2又1/25,求（ab)^2007.a-b=1/5(a-b)^2=a^2-2ab+b^2=1/25a^2+b^2=2又1/252ab=(a^2+b^2)-(a^2-2ab+b^2)=2ab=1（ab)^2007=14.不等式,（...