x2+y2-2x+6y+6=0.(x-1)^2 + (y+3)^2 = 4,圆心(1,-3),半径=2
因为“已知过点A(-1,-1)的直线L与圆x2+y2-2x+6y+6=0相交”,故圆心到该直线的距离 < 半径,设直线:y + 1 = k(x+1),kx-y+k-1 = 0,圆心到直线的距离
= 2/k+1/ / (k^2 + 1)^(1/2)
x2+y2-2x+6y+6=0.(x-1)^2 + (y+3)^2 = 4,圆心(1,-3),半径=2
因为“已知过点A(-1,-1)的直线L与圆x2+y2-2x+6y+6=0相交”,故圆心到该直线的距离 < 半径,设直线:y + 1 = k(x+1),kx-y+k-1 = 0,圆心到直线的距离
= 2/k+1/ / (k^2 + 1)^(1/2)