Question

【x-1分之x+x²-（x-1）】÷x²-2x+1分之x3次方+x²

Answer 1

由分母则x-1≠0

所以两边除以x-1

x-1=2

x=3

错了,是-(x+1)

原式=[x+x²-(x+1)²]/(x-1)*(x²-2x+1)/(x³+x²)

=(-x-1)/(x-1)*(x-1)²/x²(x+1)

=-(x+1)/(x-1)*(x-1)²/x²(x+1)

=-(x-1)/x²

=-(3-1)/3²

=-2/9