Question

设集合A是函数fx=√x+1+√2-x的定义域,集合B是函数y=x^2-1(x∈{-2,-1,0,1,2}的值域,求集合

Answer 1

由x+1≧0且2-x≧0得：-1≦x≦2,所以集合A={x/ -1≦x≦2}

由集合B是函数y=x^2-1(x∈{-2,-1,0,1,2}的值域得集合B={3,0,-1},故：集合A∩B={ 0,-1}