1、( i - i^-1)^3=[(i^2/i)-(1/i)]^3=(-2/i)^3=-8/(i^3)=-8i/(i^4)=-8i
( i - i^-1)^3 的虚部为-8i
2、( i / Z1)+( Z2/5)=[i/(2-i)]+(1+3i)/5=[i(2+i)/(2-i)(2+i)]+(1+3i)/5=[(2i-1)/5]+(1+3i)/5=i
复数( i / Z1)+( Z2/5)的虚部为i
1、( i - i^-1)^3=[(i^2/i)-(1/i)]^3=(-2/i)^3=-8/(i^3)=-8i/(i^4)=-8i
( i - i^-1)^3 的虚部为-8i
2、( i / Z1)+( Z2/5)=[i/(2-i)]+(1+3i)/5=[i(2+i)/(2-i)(2+i)]+(1+3i)/5=[(2i-1)/5]+(1+3i)/5=i
复数( i / Z1)+( Z2/5)的虚部为i