设涨价x元,则利润y元.
y=(100-90+x)(500-10x)
=(10+x)(500-10x)
=5000-100x+500x-10x²
=-10x²+400x+5000
y=-10(x-20)²+5400
由y=-10(x-20)²+5400可得:
最大利润为5400元,售价应定:100+20=120(元)
设涨价x元,则利润y元.
y=(100-90+x)(500-10x)
=(10+x)(500-10x)
=5000-100x+500x-10x²
=-10x²+400x+5000
y=-10(x-20)²+5400
由y=-10(x-20)²+5400可得:
最大利润为5400元,售价应定:100+20=120(元)