cos255°＋sin（－7π/3）＋cos（－2040°）＋sin（－16π/3）=-cos45-sin(π/3)+cos120+sin（2π/3）=-根号（2）/2-根号（3）/2-1/2+根号（3）/2=-（根号（2）+1）/2
求值：cos255°＋sin（－7π/3）＋cos（－2040°）＋sin（－16π/3）
1个回答
相关问题
-
求下列三角函数值cos225°sin11/3πsin(-16/3π)cos(-2040°)
-
求值-cosπ/16sinπ/16cosπ/8
-
cos(-16π/3)+sin(-16π/3)的值为?
-
求值【sin(2π-α)sin(π+α)cos(-π-α)】/【sin(3π-α)-cos(π-α)】
-
sin3/7π*cos2/5π-cos(-3/7π)*sin(-2/5π)
-
求值sin7π/3cos(-23π/6)+tan(-11π/4)cos13π/3
-
若tan(7π+α)=α,求sin(α+3π)+cos(π-α)/sin(-α)-cos(π+α)的值
-
sin2π／3=?；cos2π／3=?；sin7π／6=?；cos7π／6=?说下
-
求值sin(π/2)*sin(π/3)+2cos(-π/2)-根号3*tan(π/3)
-
求值:2cosπ/2-tanπ/4+3/4tan²π/6-sinπ/6+cos²π/6+sin3π/