Question

x^(lgx^2-1)=10的解集,

Answer 1

x^(lgx^2-1)=10

lgx^2-1=logx(10)

2lgx-1=1/lgx

2(lgx)^2-lgx-1=0

(2lgx+1)(lgx-1)=0

lgx=-1/2, x1=10^(-1/2)

lgx=1, x2=10