(1)3*a(n+1)2=an*(an-2*a(n+1))
(3a(n+1)-an)(a(n+1)+an)=0
an>0,3a(n+1)=an,所以an是等比数列,且an=(1/3)^(n-1)
(2)log3an=1-n
bn=1/n(log3a1+loga2+...+log3an)=1/n(0-1-2-...+1-n)=(1-n)/2
Tn=n/2-(1/2+2/2+3/2+...+n/2)=(n-n^2)/4
(Tn)max=T1=0
(1)3*a(n+1)2=an*(an-2*a(n+1))
(3a(n+1)-an)(a(n+1)+an)=0
an>0,3a(n+1)=an,所以an是等比数列,且an=(1/3)^(n-1)
(2)log3an=1-n
bn=1/n(log3a1+loga2+...+log3an)=1/n(0-1-2-...+1-n)=(1-n)/2
Tn=n/2-(1/2+2/2+3/2+...+n/2)=(n-n^2)/4
(Tn)max=T1=0