Question

集合A ={(x,y)|3/(x-2)=2/(y+1)}集合B={(x,y)|2x-3y-7=0},若全集U={（x,y

Answer 1

3/(x-2)=2/(y+1)化简得

3y+3=2x-4

2x-3y-7=0 (x≠2,y≠-1)

可见B=A∪(2,-1)

所以B∩CuA={(x,y)|x=2,y=-1}