设A(x1,y1) M(x,y)
则(x1+1)^2+y1^2=4
(x1+4)/2=x (y1+3)/2=y
x1=2x-4 y1=2y-3
代入:(x1+1)^2+y1^2=4
(2x-3)^2+(2y-3)^2=4
(x-3/2)^+(y-3/2)^2=1
这就是M的轨迹方程.
设A(x1,y1) M(x,y)
则(x1+1)^2+y1^2=4
(x1+4)/2=x (y1+3)/2=y
x1=2x-4 y1=2y-3
代入:(x1+1)^2+y1^2=4
(2x-3)^2+(2y-3)^2=4
(x-3/2)^+(y-3/2)^2=1
这就是M的轨迹方程.