Question

已知如图,AB=AC,AD=AE,角BAC=角DAE,试说明BC=CE

Answer 1

证明：∵∠DAE=∠BAC,

∴∠DAE-∠CAD=∠BAC-∠CAD,

即∠EAC=∠DAB,

∵AE=AD,AC=AB,

∴ΔAEC≌ΔADB,

∴CE=BD.

(注：不是CE=BC).