sin(2π+α)tan(π+α)/sin(3π/2-α)tam(3π-α)tan(-π-α)
=sinαtanα/[(-cosα)tan(-α)tan(-α)]
=-sinαtanα/(cosα*sinα/cosα*tanα)
=-sinαtanα/sinαtanα
=-1
sin(2π+α)tan(π+α)/sin(3π/2-α)tam(3π-α)tan(-π-α) 化简出的值是多少
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