lim(n→无穷)sin^2((√n^2+n)π)=lim(n→无穷)sin^2((√n^2+n)π-nπ)=lim(n→无穷)sin^2((n/(√n^2+n)+n)π)=sin^2(π/2)=1
lim(n→无穷)sin^2(√n^2+n)求解
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