Question

证明：1+3sin2αsec4α=sec6α-tan6α（sin、sec、tan后的数字均为平方数,数字后为阿尔法）

Answer 1

证明：令 x =(sin α)^2, 则 (cos α)^2 =1-x, (sec α)^2 = 1 /(1-x), (tan α)^2 = x /(1-x). 所以 1 +3 (sin α)^2 (sec α)^4 =1 +3x /(1...