Question

2*1001=1; (2n+2)*1001=3[（2n）*1001],则2008*1001=?

Answer 1

n=1:(2*1+2)^1001=4^1001=3*2^1001=3

n=2:(2*2+2)^1001=6^1001=3*4^1001=3*3

n=3:(2*3+2)^1001=8^1001=3*6^1001=3*3*3

所以：2008^1001=3的1003次方