① n(SO2)=1.992×10/233+16.82/104=0.247mol
n(O2)=(0.897×10/233)÷2=0.0192mol
② n (MgSO4)= 0.897×10/233= 0.0384mol
m(MgSO3)=550g×0.652/(100+0.652)=3.563g
n(MgSO3)=3.563/104=0.0343mol
由Mg(HSO3)2产生的n(BaSO4)= 1.992×10/233-0.0384-0.0352=0.0127mol
则:n[Mg(HSO3)2 ]=0.012/2=0.00635mol