IB*Rb+VBE+IB(1+β)Re=5V
所以:IB=(5-VBE)/[Rb+(1+β)Re]
IC=IBβ
VCE=6V-(-5)V-0.5ICRc-(1+β)IBRe
Au=uo/ui=-0.5ibβRc/[ibRb+ib(1+β)Re]
=-0.5ibβRc/ib[Rb+(1+β)Re]
=-0.5βRc/[Rb+(1+β)Re]
Ri=ui/ib=[ibRb+ib(1+β)Re]/ib=Rb+(1+β)Re
Ro=Rc
IB*Rb+VBE+IB(1+β)Re=5V
所以:IB=(5-VBE)/[Rb+(1+β)Re]
IC=IBβ
VCE=6V-(-5)V-0.5ICRc-(1+β)IBRe
Au=uo/ui=-0.5ibβRc/[ibRb+ib(1+β)Re]
=-0.5ibβRc/ib[Rb+(1+β)Re]
=-0.5βRc/[Rb+(1+β)Re]
Ri=ui/ib=[ibRb+ib(1+β)Re]/ib=Rb+(1+β)Re
Ro=Rc