(-2a)^6-(-3a^3)^2-[-(1/2a)^2]^3*(-2)^7=?
1个回答
(-2a)^6-(-3a^3)^2-[-(1/2a)^2]^3*(-2)^7
= 64a^6 - 9a^6 - (-a^6/2^6) * (-2)^7
= 55a^6 - 2a^6
= 53a^6
相关问题
a1=(1,2,-3) a2=(3,0,1) a3=(9,6,-7)
A1(1,1) A2(2,-4) A3(3,4) A4(4,-2) A5(5,7) A6(6,-3/4)A7(7,10)
如果3A-2B=7/9那么2/3A-B=( ),7/6-(3A-2B)+1/3=( )
如果3a-2b=[7/9],那么[3/2]a-b=______,[7/6]-(3a-2b)+[1/3]=______.
如果3a-2b=[7/9],那么[3/2]a-b=______,[7/6]-(3a-2b)+[1/3]=______.
化简,【注:a,b均为向量】1:6(3a-2b)+9(-2a+b)2:1/2[(7/3)a+b]-7/6[a+(3/7)
1/3(a^2-1)+(2a^2+3a-6)-2(a^2-3)其中a=-1
A1=(1,2,1,3)、A2=(4,-1,-5,-6)、A3=(-1,-3,-4,-7)、A4=(2,1,2,3)的秩
(1)-3ma^3+6ma^2+12ma (2)7(a-1)+x(a-1) (3)3(a-b)^2+6(b-a) (4)
等比数列满足a1+a2=3,a2+a3=6则a7=?