AE平分∠BAD,所以∠EAB=∠BAD/2
BE平分∠ABC,所以∠EBA=∠ABC/2
∠AEB=180-(∠EAB+∠EBA)=180-(∠BAD+∠ABC)/2
在四边形ABCD中,∠D=120,∠C=80
因此∠ABC+∠BAD=360-120-80=160
所以∠AEB=180-160/2=100
AE平分∠BAD,所以∠EAB=∠BAD/2
BE平分∠ABC,所以∠EBA=∠ABC/2
∠AEB=180-(∠EAB+∠EBA)=180-(∠BAD+∠ABC)/2
在四边形ABCD中,∠D=120,∠C=80
因此∠ABC+∠BAD=360-120-80=160
所以∠AEB=180-160/2=100