选讲里,使用柯西不等式
(x+y+z)[x^2/(y+x)+y^2/(x+z)+z^2/(x+y)]≥(x+y+z)^2
x,y,z是正实数
∴x+y+z>0
∴x^2/(y+x)+y^2/(x+z)+z^2/(x+y)≥x+y+z
就一步
已知x,y,z是正实数.求证x^2/(y+x)+y^2/(x+z)+z^2/(x+y)≥x+y+z/2
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