Question

英语表述的化学题What is the Voltage of the Voltaic cell Cu/Cu2+||Zn/

Answer 1

在 298K 的温度下,如果 [Zn2+}=0.2M and [Cu2+]=4.0M,那么原电池Cu/Cu2+||Zn/Zn2+的电压是多少?

E-(Zn2+/Zn) = E Ө + (0.0592V/2)×lg(0.2)= -0.7618V-0.0207V=-0.7825V

E+(Cu2+/Cu) = E Ө + (0.0592V/2)×lg(4)= 0.3419-0.0178V=0.3241V

电动势: E = E+ - E-=0.3241V+0.7825V=1.1066V