Question

求y=-2x+1/3x+1的定义域和值域

Answer 1

y=(-2x+1)/(3x+1)

=(-2x-2/3+2/3+1)/(3x+1)

=-2/3+(5/3)/(3x+1)

定义域为:{x|x≠-1/3,x属于实数}

值域为:{y|y≠-2/3,y属于实数}